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BENKO'S BRAIN TWISTERS
Problem Two
 
 

This endgame composition is very difficult and will even stump your chess computer (so feel free to turn your machines on to see if the silicon monster can get the job done).

 

WHITE TO MOVE AND WIN

This fascinating composition first appeared in the magazine, M.Sakkelet in 1972. It received 1st Prize.

1.Nb5!! A real key move which, being unexpected, deserves two exclamation marks. It is indeed surprising for it allows the Black King to escape from the mating net and, in addition, it takes the Knight further from the threatening pawn, apparently allowing it to promote. Is this key move necessary? Wouldn’t 1.Ne2 lead to the same result? No, 1.Ne2 fails to 1...h2 2.Nac3 b5 3.Nd4 b4+! 4.Kxb4 Kb2, and Black escapes since his King is out of the trap. 1...Kb1 The best try. The tempting 1...h2 loses beautifully after 2.Nac3 h1=Q 3.Nd4 Qc1+ 4.Kb3 Qb2+ 5.Kc4 b5+ 6.Kd3 Qxf2 7.Nb3+ Kb2 8.Nd1+. It’s now clear that the Black Queen was led into a trap. Due to all the possible forks, she would have been lost whether she captured the f-pawn or not. 2.Nac3+ Kc2 White wins after 2...Kc1 2.g4!. 3.Nd4+! Kd3! The obvious 3...Kxc3 runs into 4.Ne2+! (A very important move! Another obvious move is 4.Nf3? which fails to 4...b5!, when Black can draw) 4...Kc4 (4...Kd2 fails to 5.Ng1 h2 6.Nf3+, while 4...Kd3 5.Nf4+ is also easy for White) 5.g4 h2 6.Ng3 Kc3 7.Ka4 Kc4 8.g5 b5+ 9.Ka5, and White wins since he will Queen with check. 4.Nd1!! This is the only way to win. White fails to achieve the victory after 4.f4 Kxc3 5.Ne2+ Kd3, and Black wins because White no longer can play Nf4+. If White had tried 4.f3 instead of 4.f4, then 4...Kxc3 5.Ne2+ Kd2 wins since 6.Ng1 h2 7.Nf3+ isn’t possible. White can try 4.Nf3, but he still fails to win the game: 4...Kxc3 5.Ka4 Kc4 6.g4 b5+ 7.Ka5 b6+! 8.Ka6 b4 9.g5 Kd5 10.g6 Ke6 11.Ng5+ Kf6 12.Nxh3 b3 13.Nf4 b2 14.Nd5+ Kxg6 15.Nc3 Kf5, with a draw. 4...h2 5.f4 Kxd4 And not 5...h1=N 6.f5, winning for White. 6.Nf2 Kc3 6...Ke3 7.Ng4+ wins for White. 7.f5 b5 8.f6 b4+ 9.Ka2 Kc2 10.f7 b3+ 11.Ka3 b2 12.f8=Q b1=Q 13.Qf5+, 1–0.